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    Question

    Given below are two numbers series 'I' and 'II' and

    each series has a wrong (odd one out) number. The number that should come in place of the wrong number in series 'I' and 'II' are 'P' and 'Q', respectively. First find the values of 'P' and 'Q' and then find which among the given statement(s) is/are true. I: 68, 82, 92, 103, 107, 118, 122 II: 3840, 1920, 1480, 1200, 1050, 945 Statement I: One of the factors of 'P' is a double digit prime number. Statement II: 22.5% of 'Q' is a perfect square number. Statement III: The H.C.F of 'P' and 'Q' is 8.
    A Only I and III Correct Answer Incorrect Answer
    B Only II Correct Answer Incorrect Answer
    C Only I and II Correct Answer Incorrect Answer
    D All of I, II and III Correct Answer Incorrect Answer
    E Only I Correct Answer Incorrect Answer

    Solution

    For series I: The series follows the pattern as: Number + sum of digits of the number. 68 + (6 + 8) = 82 82 + (8 + 2) = 92 92 + (9 + 2) = 103 103 + (1 + 3) = 107 107 + (1 + 7) = 115 115 + (1 + 1 + 5) = 122 Therefore, 115 should come in place of 118. So, P = 115 For series II: 3840 X (1/2) = 1920 1920 X (3/4) = 1440 1440 X (5/6) = 1200 1200 X (7/8) = 1050 1050 X (9/10) = 945 Therefore, 1440 should come in place of 1480. So, Q = 1440 Statement I: Since, P = 115 = 5 X 23 And, 23 is a prime number. So, statement I is true. Statement II: 22.5% of 'Q' = 1440 X (22.5/100) = 324 Since, āˆš324 = 18 So, statement II is true. Statement III: H.C.F of 115 and 1440 = 5 ā‰  8 So, statement III is not true.

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