Question
Below given are 2 wrong number series, where ‘x’ is
the correct replacement of the wrong term of series I & ‘y’ is the correct replacement of the wrong term of series II. Series I: 50, 57, 69, 84, 100, 118 Series II: 213, 109, 111, 168, 348, 843 I. 'y' is not a multiple of 'x'. II. Adding 24 to 'y' and then dividing the result by 'x+9' leaves a remainder of 45. III. The sum of the incorrect values is divisible by 12.Solution
ATQ, Series I 50 + 7 × 1 = 57 57 + 6 × 2 = 69 69 + 5 × 3 = 84 84 + 4 × 4 = 100 100 + 3 × 5 = 115 x = 115 Series II 213 × 0.5 + 2.5 = 109 109× 1 + 2 = 111 111 × 1.5 + 1.5 = 168 168× 2 + 1 = 337 337× 2.5 + 0.5 = 843 ‘y’ = 337 I. y/x = 337/115 (True) II. (y + 24)/(x + 9) = (337 + 24)/(115 + 9) = 361/124 (False) III.118 + 348 = 466  = 466/12 (False) Hence, Only I is correct
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8
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