Question
Find the 31st term of the series 25, 29,
33……Solution
The given series is in the Arithmetic progression. having First term (a) = 25 Common difference (d) = 29 – 25 = 33 – 29 = 4 So, the nth term (an) = a + (n – 1) × d So,31st term = 25 + (31 – 1) × 4  = 25 + 30 × 4 =25 + 120 = 145
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