Question
Find the 31st term of the series 25, 29,
33……Solution
The given series is in the Arithmetic progression. having First term (a) = 25 Common difference (d) = 29 – 25 = 33 – 29 = 4 So, the nth term (an) = a + (n – 1) × d So,31st term = 25 + (31 – 1) × 4 = 25 + 30 × 4 =25 + 120 = 145
More Series Questions
√323.89 × (3.20) ÷ 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?
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