Question
Two partners, X and Y, invested in a business in the
ratio of 5:8. After 5 months, X increased his capital by 25%, and 2 months later, he increased it again by 12%. Y reduced his capital by 25% after 4 months and then increased it by 25% after 5 more months. If the total profit at the end of the year is Rs. 27,632, what is Y's share of the profit?Solution
Let the investment of X = 5 And investment of Y = 8 So, profit after one year for X will be, = (5 × 5) + (5 × 125/100 × 2) + (5 × 125/100 × 112/100 × 5) = (5 × 5) + (6.25 × 2) + (7 × 5) = 25 + 12.5 + 35 = 72.5 Similarly, profit after one year for Y will be, = (8 × 4) + (8 × 75/100 × 5) + (8 × 75/100 × 125/100 × 3) = (8 × 4) + (6 × 5) + (7.5 × 3) = 32 + 30 + 22.5 = 84.5 So, ratio of profit after one year for X and Y = 72.5 : 84.5 = 145 : 169 Thus, the profit share of Y = 27,632 × 169/314 => Rs. 14,872 Hence, the required answer = Rs. 14,872.
I. x2 - 11x + 24 = 0
II. y² - 5y + 6 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
