Question
The ratio of the selling prices of two articles, A and
B, is 3:4. Article A is sold at a profit of Rs. 540, and article B is sold at a loss of 10%. If the difference between the cost prices of the two articles is Rs. 1,080, find the cost price of article A.Solution
Let the selling prices of articles A and B be 3x and 4x, respectively. Cost price of article A = 3x - 540. Cost price of article B = 4x × 90/100 = 3.6x. According to the question: (3x - 540) - 3.6x = 1080. 3x - 3.6x - 540 = 1080. -0.6x = 1620. x = 1620 / 0.6 = 2700. Cost price of article A = 3x - 540 = 3(2700) - 540 = 8100 - 540 = 7560. Correct answer: c. 7560
√10201 × √3969 - (52)² = √? + (60)²
...20% of 550 × 25% of 80 = ?2 × 22
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
1024 ÷ 32 = 2(1/2)×?
What will come in the place of question mark (?) in the given expression?
(28/14) of 56 + ? = 920 ÷ 5
?% of 320 - 69 = 123
√? = 32% of 900 + 48% of 50
?2 × 25 = 42 × 21 + 172
18 * 9 + 25% of 120 + 50% of 200 = ?