Mr Rohila left his entire property to his wife, daughter and son and the cook. His son and daughter got half the estate, sharing in the ratio of 3:2. His wife got equal as much as his daughter. If the cook received Rs 9,000, then the entire property was worth:
Let the entire property be Rs x Part of son and daughter together = 1/2 x Ratio of son and daughter = 3:2 Son get = 3/5×1/2 x Daughter get = 2/5 × 1/2 x Wife get = 2/5 × 1/2 x Cook get = Rs 9,000 ⇒ x - (3x/10+ 2x/10+ 2x/10) = 9,000 ⇒x - ((3x+2x+2x)/10) = 9,000 ⇒3x/10= 9,000 ∴ x = 30,000 ALTERNATE METHOD: Let the entire property = 100% His sons & daughters got 50% in 3:2 means that share of his sons = 30% & that of daughter = 20% So share of wife = 20% Hence remaining share is of cook So 30% of entire property = 9000 Hence entire property = 9000×100/30 = 30,000
(? + 2180) ÷ 69 × 5 = 450
85% of 620 + ? % of 1082 = 4855
1780 – 60 ÷ 4 x 80 = ?
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
25% of 300 + √(?) = 35% of 600 - 15% of 300
(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²
26% of 950 + 50/3% of 7962 = ?
((8)0- (0.1)-1)/( (6/16)-1 ×(3/2)3+ ((-2)/6)-1) = ?/2
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2