Question
In an alloy of three metals, ratio of the quantity of
gold, silver and platinum is 5:6:8, respectively. If total quantity of silver and platinum together is 140 kg then find the difference between the quantity of silver and gold.Solution
Let the quantity of gold, silver and platinum be β5xβ kg, β6xβ kg and β8xβ kg, respectively. Total quantity of silver and platinum together = 140 kg 6x + 8x = 140 Or, x = 10 Difference between the quantity of silver and gold = {(6 β 5) Γ 10} = 10 kg
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5Β³ + 3Β²) Γ 2 = ? (1225/25) - (192/96) + (50/5) = ?

What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) Γ· 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 β 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650