Question
In an alloy of three metals, ratio of the quantity of
gold, silver and platinum is 5:6:8, respectively. If total quantity of silver and platinum together is 140 kg then find the difference between the quantity of silver and gold.Solution
Let the quantity of gold, silver and platinum be β5xβ kg, β6xβ kg and β8xβ kg, respectively. Total quantity of silver and platinum together = 140 kg 6x + 8x = 140 Or, x = 10 Difference between the quantity of silver and gold = {(6 β 5) Γ 10} = 10 kg
`[(sqrt(750) xx15.981) -: 54.003]` `xx` ? = 6997.81001
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
(95.89% of 625.15 + 36.36% of 499.89) Γ· 6.02 = ? β 269.72
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
(2999.77 Γ· 74.85) + (β624.95 Γ 4.09) = ?
...? = 38.97Β² Γ· (3.99β΅ + 5.89 Γ 107.32) + 58.24% of (512.12 Γ 21.07)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
2β574 + 19.956% of 1449.978 = ?% of 628.08
(24.98)2 = ?2Β + (14.99)2
21% of 6600 + 453.987 =?