Question
Difference between the ages of A and B is same as the
difference between the ages of B and C. The difference between the ages of A and C is 8 years. If their sum of age is 42, then find the ratio of ages of three people.Solution
According to question, => A – B = B – C => A + C = 2B => A – C = 8 => A = 8 + C => A + B + C = 42 => 2B + B = 42 => B = 14 Now, => A + B + C = 42 => C + 8 + 14 + C = 42 => 2C = 20 => C = 10 Age of A = 8 + 10 = 18 Required ratio = 18:14:10 = 9:7:5
Statements: U & K # X % I % W; T # M $ W; T @ N @ S
Conclusions:
I. X @ M
II. K $ S
III. N # I
Statements: Y $ Z, H $ D, Z * D
Conclusions: a) Y & H b) Y * D
...Statements: P @ Q, Q # R, R % S
Conclusions: a) P # R b) P @ S
Statements: V ≤R = W ≥ Q, U = T ≥ S < X, U < Q
Conclusions: I. V < Q II. Q > X
Statements: B @ E, E $ Y, Y & I, I % C
Conclusions: I. E @ I II. C & B
...Statements: N = Q < X ≤ L, L > T = G ≥ E
Conclusions:
I. L ≥ Q
II. G > X
III. L > N
Statements: U > G = L > V < K ≤ C > S < N
Conclusion I: U ≥ V
II: C > V
Statement: B = E ≥ F ≥ M < J < V ≥ R; M > A
Conclusion:
I. A ≥ R
II. B > A
...Statements: K * D, D $ N, N % M, M © W
Conclusions: I.M % W II.M $ W III.N @ D�...
Statements: P % Q, P $ R, Q # S, R @ T
Conclusions:
I. R $ Q
II. S & T �...