Question
A man is supposed to distribute Rs. 4000 among his three
sons, A, B, and C in the ratio of 3:2:3, respectively, but mistakenly he distributed in the ratio of 5:2:3, respectively. Find the difference between amount received by A mistakenly and the amount that A should have actually receivedSolution
Amount that should be received by A initially = [3/(3 + 2 + 3)] × 4000 = Rs. 1500 Amount received by A mistakenly = [5/(5 + 2 + 3)] × 4000 = Rs. 2000 Therefore, required difference = 2000 – 1500 = Rs. 500
What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
143 Â Â Â Â 119Â Â Â Â 107Â Â Â Â 101Â Â Â Â Â 98Â Â Â Â ?
96 89 ? 90 94 91
...What value should come in the place of (?) in the following number series?
19, 235, 260, 324, 333, ?
What will come in place of the question mark (?) in the following series?
305...
In each of the following number series, one term is missing. Find the missing term.
3, 5, 20, 24, 144, 150, ?
1029, 1030, 1039, 1064, ?, 1194
75, 80, 95, ?, 155, 200
What will come in place of the question mark (?) in the following series?
1515, 184, ?, 455, 967, 624
7 29 61 ? 211 349
...
