Question
Ratio between marked price of article A to article B is
5:6. Shopkeeper allowed d% discount on article ‘A’ and (d + 16)% discount on article ‘B’, so selling price of both articles become equal. If shopkeeper made a profit of 25% on article A and 35% on article B and profit made on article B is Rs. 1224 more than that of article A, then find the cost price of article ‘A’ and article ‘B’ respectively?Solution
Let marked price of article A and B be 500x and 600x respectively. According to question, 500x × (100 – d)/100 = 600x × (100 – d − 16)/100 500 – 5d = 600 – 6d - 84 ⇒ d = 16% Cost price of article A = 500x × (84/100) × (100/125) = Rs 336x Cost price of article B = 600x × (65/100) × (100/130) = Rs 300x According to question, (600x × 70/100 – 300x) – (500x × 84/100 – 336x) = 1224 120x – 84x = 1224 ⇒ x = 34 Cost price of article A = 34 × 336 = Rs. 11424 Cost price of article B = 34 × 300 = Rs. 10200
The class NP-complete includes problems that are:
Which of the following is NOT a method for handling deadlocks?
Which of the following statements is true regarding the class NP?
What is a deadlock in a computer system?
Which famous sorting algorithm uses the divide-and-conquer strategy?
Which data structure in a compiler is used for managing information about variables and their attributes?
Which command will help you to find the time of how long the system is being running?
In which case higher bandwidth can be achieved
What is an algorithm?
In the context of ADTs, what does "encapsulation" refer to?