Question
The numbers ‘A’, ‘B’ and ‘C’ are in the
ratio 2:3:5. If the difference between the largest number ‘C’ and the smallest number ‘A’ is 393, what is the total sum of ‘A’, ‘B’ and ‘C’?Solution
Let ‘A’, ‘B’ and ‘C’ be ‘2x’, ‘3x’ and ‘5x’, respectively. ATQ; 5x – 2x = 393 Or, 3x = 393 So, x = 131 Required sum = 2x + 3x + 5x = 10x = 10 × 131 = 1310
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