Question
The numbers βAβ, βBβ and βCβ are in the
ratio 2:3:5. If the difference between the largest number βCβ and the smallest number βAβ is 393, what is the total sum of βAβ, βBβ and βCβ?Solution
Let βAβ, βBβ and βCβ be β2xβ, β3xβ and β5xβ, respectively. ATQ; 5x β 2x = 393 Or, 3x = 393 So, x = 131 Required sum = 2x + 3x + 5x = 10x = 10 Γ 131 = 1310Β
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