Let money received by men and women be 5x and 4x respectively. As per the question, 5x + 4x = 3,60,000 ⇒9x = 3,60,000 ⇒ x = 40,000 Amount received by men = 40,000 ×5 = Rs. 2,00,000 and amount received by women = 40,000 ×4 = Rs. 1,60,000 Let number of men = a and number of women =66 – a Amount received by each man = 200000/a and amount received by each women = 160000/66 - a As per the question, ⇒ (200000/a)/ ( 160000/66 - a) = 3/2 ⇒ (200000/a) × (66 - a)/160000 = 3 /2 ⇒ 5 ( 66 - a) / 4a = 3 /2 ⇒660 – 10a = 12a ⇒22a = 660 a = 30 Number of men = 30
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. x ² + 5 x + 6 = 0
II. y²+ 7 y + 12= 0
...Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root o...
I. x2– 9x + 18 = 0
II. y2– 5y + 6 = 0
I. p2 +7p + 10 = 0 II. q2- q – 6 = 0
I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
Equation 1: x² - 90x + 2025 = 0
Equation 2: y² - 88y + 1936 = 0
