Question
The cost of diamond varies directly as the square of its
weight. A diamond broke into four pieces with weights in the ratio 3 : 4 : 5 : 6. if the loss in the total value of the diamond was Rs. 119,000. The price of the original diamond was?Solution
Let the weight of the pieces of diamond be 3x, 4x, 5x, 6x Total weight of diamond = 3x + 4x + 5x + 6x = 18x Price ∝ (weight)2 => Price = k(weight)2 ; where, K is constant Original price = k(18x)2 Price of pieces = (9kx2 + 16kx2 + 25kx2 + 36kx2) = 86kx2 Loss in price = 324kx2 – 86kx2 = 238kx2 which is given as 119,000 => 238kx2 = 119000 => kx2 = 500 Original price = 324kx2 = 324 x 500 = 162000
l. x2 - 16x + 64 = 0
II. y2 = 64
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. 3 x² - 10
