Question
Two quantities are
given as Quantity I and Quantity II. You have to determine the relationship between them and give the answer. The efficiencies of a man and a boy are in the ratio 7 : 4. For a building project, 2 men and 3 boys together can finish the job in 12 days. Quantity I: In how many days will 3 men and 2 boys complete the entire job? Quantity II: If the man’s efficiency increases by 20% and the boy’s by 10%, how many days will one man and one boy take to finish 75% of the same job?Solution
ATQ, Let efficiencies be 7x (man) and 4x (boy). Total work = (27x + 34x) * 12 = (14x + 12x) * 12 = 26x * 12 = 312x From Quantity I, Efficiency of 3 men and 2 boys = 37x + 24x = 21x + 8x = 29x Required time = 312x / 29x = 312/29 = ~10.76 days From Quantity II, New man efficiency = 7x * 120/100 = 8.4x New boy efficiency = 4x * 110/100 = 4.4x Total = 8.4x + 4.4x = 12.8x Work to be done = 312x * 75/100 = 234x Required time = 234x / 12.8x = ~18.28 days Thus, Quantity I < Quantity II
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
[(40)2 ÷ 32 × 4] ÷ 50 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?
Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
Find the value of 16 x [(8 - 5) of 12 ÷ 4].
961 × 4 ÷ 31 – 15% of 180 = ? – 73
- What will be come in place of (?) in the given expressions.
(3/4 of 480) – (2/5 of 350) = ? 26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
Find the value of 27 ÷ 2 of 16 of [6 ÷ 8 of (6 ÷ 2 + 5)] + (10 ÷ 2.5 + 1)
What will come in the place of question mark (?) in the given expression?
28 × 15 + 48% of ? = 780
