Question
If (y/5) = 11/(z+1). Value of 'y' is root of
p2 - 10p + 25 = 0. Quantity I: Value of 10z. Quantity II: 100 In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II.Solution
ATQ, The quadratic equation is p2 −10p + 25 = 0. Solving for p:
Use the given relation to find 'z'.
From (y/5) = 11/(z+1) =
Calculate Quantity I = Quantity I = 10z = 10 × 10 = 100
Compare Quantity I and Quantity II = Quantity I = 100 and Quantity II = 100
Hence, Quantity-I = Quantity-II or No relation .
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44 45 41 50 ? 59 23
...221, 100, 0, -81, ?
...900 90 18 ? 2.16 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187