Start learning 50% faster. Sign in now
ATQ, Let the total work be 120 units. {LCM (24 and 40) } So, efficiency of 'Aman' = (120/24) = 5 units/day And efficiency of 'Bhuvan' = (120/40) = 3 units/day Let the efficiency of 'Chintu' be 'p' units/day ATQ: (5 + p) × 5 = (5 + 3) × (5 × 1.375) Or, (5 + p) = 8 × 1.375 Or, 5 + p = 11 So, 'p' = 6 Also, efficiency of 'Chintu' = 6 units/day Quantity I: Time taken by 'Chintu' to finish the work alone = (120/6) = 20 days So, Quantity I = 20 days Quantity II: Work done by 'Aman' and 'Bhuvan' in first five days = 5 × (5 + 3) = 40 units And work done by 'Aman' and 'Chintu' in last 5 days = 5 × (5 + 6) = 55 units And work done by 'Aman' alone = 120 - (55 + 40) = 25 units So, 'Aman' worked alone for 25 ÷ 5 = 5 days So, 'Aman' worked for a total of (5 + 5 + 5) = 15 days So, Quantity II = 15 days So, Quantity I > Quantity II
(8.083.03 + 59.59% of 839.83) ÷ 16.06 × 24.04 = ?3 + 1012.12
59.978% of 800.315 - 229.95 = ? - 24.95% of 200.15
13.232 + 19.98% of 549.99 = ? × 8.99
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
(44.85% of 799.77 - √143.84)² ÷ (9/11 × 76.77) = ?
25.13% of 39.89% of 74.78% of 60.21% of ? = 44.89
20% of 80 × 26% of 65 = ?
999.99 + 99.99 + 99= ?