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    Question

    Quantity I: Ajay invested a sum at a simple interest

    rate of 'x'% per annum, and it becomes 8 times its original value in 14 years. Determine the value of 'x'. Quantity II: Rs. 10,000 is invested in each of the two SIPs, 'P' and 'Q', for 2 years. Both SIPs offer interest at a rate of 8% per annum. If the difference between the interests received from the two SIPs is Rs. 'a', where SIP 'Q' compounds annually and SIP 'P' offers simple interest, find the value of 'a'. In the question, two quantities, I and II, are provided. You need to solve both quantities to establish the correct relationship between Quantity I and Quantity II and choose the correct option.
    A Quantity-I > Quantity-II Correct Answer Incorrect Answer
    B Quantity-I < Quantity-II Correct Answer Incorrect Answer
    C Quantity-I ≤ Quantity-II Correct Answer Incorrect Answer
    D Quantity-I = Quantity-II or No relation Correct Answer Incorrect Answer
    E Quantity-I ≥ Quantity-II Correct Answer Incorrect Answer

    Solution

    ATQ, Quantity I: Let, Principle = Rs.'a' Amount = Rs. '8a' Therefore, interest received = 8a – a = Rs. 7a Then, {a × x × (14/100)} = 7a Or, x = 50 Quantity II: ATQ, Difference between the interests received = P × (R/100)2 = 10000 × (8/100)2 = Rs. 64 Therefore, a = 64

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