Question
In this problem, you are presented with two quantities,
Quantity I and Quantity II.calculate both quantities and determine the correct relationship between them. Quantity I: Determine the number of factors of the number 20. Quantity II: If 'a%' of 200 is 8 more than 'b%' of 400, then find the value of (a - 2b). Now, compare Quantity I and Quantity II to establish the correct relationship between them and choose the appropriate option.Solution
ATQ, Quantity I: Factors of 20 = 1, 2, 4, 5, 10, and 20 So, number of factors of 20 = 6 So, Quantity I = 6 Quantity II: ATQ: (a/100) Γ 200 = (b/100) Γ 400 + 8 Or, 2a = 4b + 8 Or, a = 2b + 4 So, required value = 2b + 4 - 2b = 4 So, Quantity II = 4 So, Quantity I > Quantity II
Evaluate:
β729 + β49 - β16 + 1/β64
Simplify:

(1/5)(40% of 800 β 120) = ? Γ 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 β 20% of 5280) = ? Γ· 3
β157464 =?