Question
Quantity I: What will be the difference between
compound interest and simple interest for 4 years on a principal of Rs.20480 at the rate of 25% per annum? Quantity II: Rs 8079 In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity I and Quantity II and choose the correct option.Solution
Quantity I: S.I = 25 × 4 = 100% of 20480 S.I = Rs.20480 For C.I, 25% = 1/4 P = 4, A = 5 P for 4 years = 44 = 256 ratio A for 4 years = 54 = 625 ratio Interest = 625 - 256 = 369 ratio => 256 ratio = 20480 ∴ 369 ratio = (20480/256) × 369 = Rs.29520 Required difference = Rs.9040 Quantity II: Rs.8079 Hence, Quantity I > Quantity II
85.22 of 499.98% + 299.99 ÷ 30.18 = ?
783 ÷ 42.59 × 25.86 =?
118.95 – 24.10 + (91.90 ÷ 22.89 × 12.14) = ?
What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)<...
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
? = 16.08 + 13.99 × 25.07
(23.99)2 – (17.99)2 + (1378.88 + 44.88) ÷ ? = 607.998
25.31% of 5199.90 + (19.9 × 17.11) + 46.021 =? + 168.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?% of (144.31 ÷ 17.97 × 60.011) = 239.98
