Quantity I: Both can complete the work in 300/8 = 37.5 days Work done in (37.5 – 6) days = 31.5 × 8 = 252 unit Remaining work = 300 – 252 = 48 unit After B drops out remaining part will be completed by A in = 48/3 = 16 days Total time taken = 31.5 + 16 = 47.5 days Actual time taken = 37.5 days Difference = 47.5 – 37.5 = 10 days Quantity II: 5W = 4M 1W = (4/5) M Let the no. of days required to complete the work is D. 10 × 60W × D = 24M × 20 × 12 10 × (60×4)/5 M × D = 24M × 20 × 12 D= 12 days Hence, Quantity I < Quantity II .
61, 48, ?, 35, 87, 22
20 25 54 165 662 ?
...17 ? 2142 12852 64260 257040
...31 35 60 124 ? 441
...? 12 24 44 74 116
...64 48 36 22 16 8
25 13.5 12.5 20.75 39.5 ? 302.25
...6 10 ? 210 1672 16710
...Direction: Which of the following will replace ‘?’ in the given question?
2, ‘?’, 46, 136, 311, 605, 1086
12 23 65 ? 1239 7409
...