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Quantity I: Both can complete the work in 300/8 = 37.5 days Work done in (37.5 – 6) days = 31.5 × 8 = 252 unit Remaining work = 300 – 252 = 48 unit After B drops out remaining part will be completed by A in = 48/3 = 16 days Total time taken = 31.5 + 16 = 47.5 days Actual time taken = 37.5 days Difference = 47.5 – 37.5 = 10 days Quantity II: 5W = 4M 1W = (4/5) M Let the no. of days required to complete the work is D. 10 × 60W × D = 24M × 20 × 12 10 × (60×4)/5 M × D = 24M × 20 × 12 D= 12 days Hence, Quantity I < Quantity II .
∛857375 + ∛91125 = ? + √6889
10³ = (? – 6) × 320 ÷ 8
What is the value of 7/9-11/12+12/16-1/8?
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
The alarms of two alarm clocks sound at regular intervals of 72 seconds and 80 seconds. If they beep together for the first time at 6:00 am, at what tim...
(5⁴) 5 × (25³)³=?
?% of 740 – 8% of 650 = 7.2
(√576 + √256)% of 1800 = ?
10% of 80% of 50% of ? = 4