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Quantity I: Both can complete the work in 300/8 = 37.5 days Work done in (37.5 – 6) days = 31.5 × 8 = 252 unit Remaining work = 300 – 252 = 48 unit After B drops out remaining part will be completed by A in = 48/3 = 16 days Total time taken = 31.5 + 16 = 47.5 days Actual time taken = 37.5 days Difference = 47.5 – 37.5 = 10 days Quantity II: 5W = 4M 1W = (4/5) M Let the no. of days required to complete the work is D. 10 × 60W × D = 24M × 20 × 12 10 × (60×4)/5 M × D = 24M × 20 × 12 D= 12 days Hence, Quantity I < Quantity II .
31 40 51 64 79 ?
63, 74, ?, 129, 173, 228
Choose the missing term?
B, D, F, I, L, P, ?
What will come in the place of questions (?) mark in the following questions.
40, 25, 30, 50, 105, ?
16, 16, 32, 96, ?, 1920
25 54 ? 228 460 924
...12 48 192 ? 3072 12288
...5 6 15 40 89 170 ?
...5, 23, 18, 36, 31, ?
16, 15, 24, -1, 48, ?