Question
Quantity I : Number of days the work is extended beyond
normal days. A can do a piece of work in 100 days and B in 60 days. Both of them start working together and 6 days before the scheduled completion, B drops out. Quantity II : Number of days required to complete the work working 10 hrs daily by 60 women working together. 24 men take 20 days working 12 hrs daily to do a piece of work, if 5 women do as much work as 4 men.Solution
Quantity I: 
Both can complete the work in 300/8 = 37.5 days Work done in (37.5 – 6) days = 31.5 × 8 = 252 unit Remaining work = 300 – 252 = 48 unit After B drops out remaining part will be completed by A in = 48/3 = 16 days Total time taken = 31.5 + 16 = 47.5 days Actual time taken = 37.5 days Difference = 47.5 – 37.5 = 10 days Quantity II: 5W = 4M 1W = (4/5) M Let the no. of days required to complete the work is D. 10 × 60W × D = 24M × 20 × 12 10 × (60×4)/5 M × D = 24M × 20 × 12 D= 12 days Hence, Quantity I < Quantity II .
A rise in the general level of prices in an economy is termed as?
Which plants are mentioned as good options for hanging containers?
SSNM aims at supplying
Which was the first plant bacterial disease reported?
Anion exchange capacity is found maximum in the case of:
Napier X Bajra hybrid is a cross between:
Zeno is a variety of
It is the tendency of some crops to absorb and accumulate nutrients far in excess of their actual needs if it is present in sufficiently large quantiti...
ULV spraying of herbicides refers to
Which process occurs in the mesophyll cells of C4 plants during the Hatch-Slack cycle?
Relevant for Exams:
