Question
'R' started his journey from point 'X' towards point 'Y' at
40 km/h. Three hours later, 'S' left point 'X' towards point 'Y' at 70 km/h. 'T' left point 'X' towards 'Y' after 'M' hours of 'R's journey at 105 km/h. If both 'S' and 'T' overtook 'R' at the same time, find the value of M.Solution
ATQ,
Distance covered by 'R' in the first three hours = 40 × 3 = 120 km
Relative speed of 'S' with respect to 'R' = 70 − 40 = 30 km/h
Time taken by 'S' to overtake 'R' = 120 ÷ 30 = 4 hours
Distance covered by 'S' in 4 hours = 70 × 4 = 280 km
Time taken by 'T' to cover 280 km = 280 ÷ 105 = 2.67 hours
So, 'T' must have left 2.67 hours before 'S' overtook 'R', i.e., 4 − 2.67 = 1.33 hours after 'S' left
Therefore, M = 3 + 1.33 = 4.33 hours
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
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