Question
Find the area enclosed between the curve y = √(25 –
x²) and the x-axis in the first quadrant.Solution
We are given the curve: y = √(25 – x²) This is the upper half of a circle with equation: x² + y² = 25
⇒ a circle of radius 5, centered at the origin. We are asked to find the area enclosed between the curve and the x-axis in the first quadrant, i.e., one-fourth of the area of the full circle. Area of full circle = πr² = π × 25 = 25π So, area in the first quadrant = (1/4) × 25π = 25π / 4
If  3  12  108  x   43200
Then, 47% of (x + 72)= ?
6 , 21, 116, ?, 4674, 33593
A series is 4, 5, 17, 88, 620, 5585
If another series a, b, 23, d, e, f follows the same pattern as the given number series, then find the approx...
14, 7.5, 8.5, 14.25, 30.5, ?
2 3 4 15 56 ?
...14Â Â Â Â Â 15Â Â Â Â Â Â Â 32Â Â Â Â Â Â 99Â Â Â Â Â Â 400Â Â Â Â Â Â ?
...12, 23, 68, 271, 1354, ?
11     28    47    70     ?      130
...7Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 26Â Â Â Â Â Â Â Â Â Â Â 63Â Â Â Â Â Â Â Â Â Â Â 126Â Â Â Â Â Â Â Â Â Â 215Â Â Â Â Â Â 342
...30    32    67    206    ?     4166
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