Question
If |x + 1| + |x β 2| β₯ 4, then x lies in:
Solution
Given Inequality: |x + 1| + |x β 2| β₯ 4 Identify the critical points where the expressions inside absolute values change sign. The critical points are:
- x + 1 = 0 β x = -1
- x - 2 = 0 β x = 2
- x + 1 < 0, so |x + 1| = -(x + 1) = -x - 1
- x - 2 < 0, so |x - 2| = -(x - 2) = -x + 2
- x + 1 β₯ 0, so |x + 1| = x + 1
- x - 2 < 0, so |x - 2| = -(x - 2) = -x + 2
- x + 1 > 0, so |x + 1| = x + 1
- x - 2 β₯ 0, so |x - 2| = x - 2
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