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We want to evaluate the limit: 
\ As x→0, the numerator approaches e0 − 1 − 0 = 1 – 1 – 0 = 0, and the denominator approaches 02 = 0. So, we have an indeterminate form of type 0/0and we can use L'Hôpital's Rule. Applying L'Hôpital's Rule once: 
As x→0, the numerator approaches e0 −1 = 1 – 1 = 0, and the denominator approaches 2(0)=0. We still have an indeterminate form of type 0/0, so we apply L'Hôpital's Rule again. Applying L'Hôpital's Rule a second time: 
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