Question
‘P’ who is 20% more efficient than ‘Q’ can
finish a work in 15 days. ‘P’ and ‘Q’ start working together, but ‘Q’ leaves after 6 days. The remaining work is completed by ‘P’ alone in ‘y’ days. Find the value of ‘y’.Solution
ATQ,
Time taken by ‘Q’ to complete the work = 1.2 × 15 = 18 days
Let the total work be 90 units
Efficiency of ‘P’ = 90/15 = 6 units/day
Efficiency of ‘Q’ = 90/18 = 5 units/day
Work completed by ‘P’ and ‘Q’ in 6 days = (6 + 5) × 6 = 66 units
Therefore, y = (90 – 66)/6 = 4
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