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    Question

    Two friends, Ammu and Beenu, had some candies. One of

    them had 10 more candies than the other. The candies Ammu had were 60% of the total candies they had. How many candies did each have? 
    A 30, 50 Correct Answer Incorrect Answer
    B 20, 40 Correct Answer Incorrect Answer
    C 40, 50 Correct Answer Incorrect Answer
    D 20, 30 Correct Answer Incorrect Answer

    Solution

    Let the number of candies Ammu has = x

    Let the number of candies Beenu has = y

    Acc to the question, One has 10 more candies than the other.

    So, x = y + 10 or y = x + 10 (We'll decide which one fits later)

    Ammu has 60% of the total candies:

    x = 60 % of  (x + y )

    x = 60% of (x + y)

    x = 0.6 (x + y ) 

    put the value (y + 10) in place of x, we get 

    y + 10 = 0.6(y + 10 + y)

    4 = 0.2 y

    y = 20

    now, x = 20 + 10 = 30.

    So ammu has 30 candies and Beenu has 20 candies

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