Question
Two friends, Ammu and Beenu, had some candies. One of
them had 10 more candies than the other. The candies Ammu had were 60% of the total candies they had. How many candies did each have?Solution
Let the number of candies Ammu has = x
Let the number of candies Beenu has = y
Acc to the question, One has 10 more candies than the other.
So, x = y + 10 or y = x + 10 (We'll decide which one fits later)
Ammu has 60% of the total candies:
x = 60 % of (x + y )
x = 60% of (x + y)
x = 0.6 (x + y )
put the value (y + 10) in place of x, we get
y + 10 = 0.6(y + 10 + y)
4 = 0.2 y
y = 20
now, x = 20 + 10 = 30.
So ammu has 30 candies and Beenu has 20 candies
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