Two friends, Ammu and Beenu, had some candies. One of

Solution

Let the number of candies Ammu has = x

Let the number of candies Beenu has = y

Acc to the question, One has 10 more candies than the other.

So, x = y + 10 or y = x + 10 (We'll decide which one fits later)

Ammu has 60% of the total candies:

x = 60 % of  (x + y )

x = 60% of (x + y)

x = 0.6 (x + y ) 

put the value (y + 10) in place of x, we get 

y + 10 = 0.6(y + 10 + y)

4 = 0.2 y

y = 20

now, x = 20 + 10 = 30.

So ammu has 30 candies and Beenu has 20 candies