Question
Pawan, Qureshi, and Rittu can run 120 meters in 't'
seconds, 't−2' seconds, and 't+3' seconds respectively. The speeds of Pawan and Rittu are in the ratio 5:4. Quantity I: In a 300-meter race between Qureshi and Rittu, what will be the distance between them at the moment the winner finishes the race? Quantity II: In a 320-meter race between Pawan and Rittu, what will be the distance between them at the moment the winner finishes the race? In the question, two quantities i.e. Quantity I and Quantity II are given. Solve the given quantities to establish the correct relation between them and choose the correct optionSolution
ATQ, 120 = 5 × t = 4 × (t + 3) 5t = 4t + 12 t = 12 Speed of Pawan = 120/12 = 10 m/s Speed of Qureshi = 120/(12 - 2) = 120/10 = 12 m/s Speed of Rittu = 120/(12 + 3) = 120/15 = 8 m/s Quantity I, Distance between Qureshi & Rittu, when winner finish the race = 300 - 300/12 × 8 = 300 - 200 = 100 m Quantity II, Distance between Pawan & Rittu, when winner finish the race = 320 - 320/10 × 8 = 320 - 256 = 64 m Hence, Quantity I > Quantity II
Evaluate: 360 ÷ [ {18 − (6×2)} × 5 ] + 72 − 33
(43)² - (28)² + (32)² = ?% of 2500
Evaluate:
√729 + √49 - √16 + 1/√64
What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?62 of 8 - 320 ÷ 4 = ?3 + 200
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
What will come in the place of question mark (?) in the given expression?
30% of 520 + 16% of 1500 = ? + 244
60% of 120 – ?% of 64 = 20% of 200
35% of 840 + 162 = ? – 25% × 300
20% of 240 + 18% of 200 = ?
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