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    Question

    Pawan, Qureshi, and Rittu can run 120 meters in 't'

    seconds, 't−2' seconds, and 't+3' seconds respectively. The speeds of Pawan and Rittu are in the ratio 5:4. Quantity I: In a 300-meter race between Qureshi and Rittu, what will be the distance between them at the moment the winner finishes the race? Quantity II: In a 320-meter race between Pawan and Rittu, what will be the distance between them at the moment the winner finishes the race? In the question, two quantities i.e. Quantity I and Quantity II are given. Solve the given quantities to establish the correct relation between them and choose the correct option
    A Quantity I > Quantity II Correct Answer Incorrect Answer
    B Quantity I < Quantity II Correct Answer Incorrect Answer
    C Quantity-I ≥ Quantity-II Correct Answer Incorrect Answer
    D Quantity I ≤ Quantity II Correct Answer Incorrect Answer
    E Quantity I = Quantity II or relation can be established Correct Answer Incorrect Answer

    Solution

    ATQ, 120 = 5 × t = 4 × (t + 3) 5t = 4t + 12 t = 12 Speed of Pawan = 120/12 = 10 m/s Speed of Qureshi = 120/(12 - 2) = 120/10 = 12 m/s Speed of Rittu = 120/(12 + 3) = 120/15 = 8 m/s Quantity I, Distance between Qureshi & Rittu, when winner finish the race = 300 - 300/12 × 8 = 300 - 200 = 100 m Quantity II, Distance between Pawan & Rittu, when winner finish the race = 320 - 320/10 × 8 = 320 - 256 = 64 m Hence, Quantity I > Quantity II

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