Question
A and B together can complete a work in 12 days. B alone
can complete the same work in 30 days. In how many days will A alone complete the work?Solution
Let the total work be 1 unit. A + B’s 1-day work = 1/12, and B’s 1-day work = 1/30. A’s 1-day work = 1/12 - 1/30 = 3/60 = 1/20. So, A alone will complete the work in 20 days. Answer: d) 20 days.
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
I. x²  – 44x + 468 = 0
II. y²  – 30y + 216 = 0
 If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. x ² + 5 x + 6 = 0                Â
II. y²+ 7 y + 12= 0
...I. x + 1 = 3√ 9261
II. y + 1 = √ 324
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. x2 – ...
I. 15/(√x)+9/(√x)=11√x
II. (√y)/4 + (5√y)/12 = 1/(√y)
I. 2x2 – 25x + 33 = 0
II. 3y2 + 40y + 48 = 0
