Question
A woman is 4 times as old as her daughter. In 8 years,
the woman will be twice as old as her daughter. What are their current ages?Solution
Let the current age of the daughter be y years. Then, the current age of the woman is 4y years. In 8 years: Woman's age = 4y + 8 Daughter's age = y + 8 According to the problem: 4y + 8 = 2(y + 8) => 4y + 8 = 2y + 16 => 4y - 2y = 16 - 8 => 2y = 8 => y = 4 Thus, the current age of the daughter is 4 years, and the woman's age is: Woman's age = 4y = 4(4) = 16 years. Correct Answer: d) Woman: 16 years, Daughter: 4 years
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