Question
Two pipes A and B can fill a tank in 12 hours and 16
hours, respectively. A third pipe C can empty the tank in 24 hours. If all three pipes are opened together, how long will it take to fill the tank?Solution
Work done by A in 1 hour = 1/12. Work done by B in 1 hour = 1/16. Work done by C in 1 hour = −1/24. Net work done in 1 hour = 1/12 + 1/16 − 1/24. LCM of 12, 16, and 24 is 48. Net work done in 1 hour = (4 + 3 − 2)/48 = 5/48. Time taken to fill the tank = 48/5 = 9.6 hours. Ans. b
More Quant Miscellaneous Questions
Simplify the following expression and find the final value:
(18 ÷ 6 of 2 + 7 of 5) ÷ 5
(54/6) × 5 + 12 × (17/2) = ?% of 700
(62 - 52 ) % of 800 = 22 X √?
√49 + √144% of 3600 = ?
- 45% of 160 – 25% of 80 = 20% of ?
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Find the Value of √(-√3+√(3+8√(7+4√3)))?
Simplify:
(3/5 of 250) + (25% of 160) - (0.2 of 150)
√(?) ² = √7396 - √6889
