Question
A right circular cone has a base radius of 4 cm and a
height of 9 cm. If a cylindrical hole of radius 2 cm is drilled through the axis of the cone, what is the volume of the remaining solid?Solution
Volume of the cone = (1/3) * π * r² * h = (1/3) * π * (4²) * 9 = (1/3) * π * 16 * 9 = 48π cm³. Volume of the cylindrical hole = π * r² * h Where r = 2 cm and height of the cone = 9 cm: Volume of the hole = π * (2²) * 9 = π * 4 * 9 = 36π cm³. Remaining volume = Volume of cone - Volume of hole = 48π - 36π = 12π cm³. Correct option: a) 12π cm³
6Â Â Â Â Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â Â Â Â Â 15Â Â Â Â Â Â Â Â Â Â 46Â Â Â Â Â Â Â Â Â Â 185Â Â Â Â Â Â Â Â ?
...1, 27, ?, 343, 729, 1331
3 12 48 192 768 ?
Find the odd one out: 11, 13, 17, 19, 21
6   55   91   116   132    ?  . Â
24Â Â Â 72Â Â Â Â 180Â Â Â Â 360Â Â Â Â Â 540Â Â Â ?
96Â Â Â 111Â Â Â 131Â Â Â ? Â Â Â Â Â 186Â Â Â Â 221
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I:Â Â Â 210, P , 233, 64,...
13 24 75 134 447 892
...Complete the series.
19, 23, 26, 30, 33, ?
