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From I and II: We have number of days in which 12 girls can complete the work. So using efficiency we can find the number of days required by boy to complete the work and then the required answer From II and III: We have number of days in which 12 girls can complete the work. So days required by child can be find out, and then by boys. From I and III: We get 3 equations in 3 variables – boy, girls and child. So can be found.
The present age of A is 5/3 times to that of his marriage age. Present age of his brother is 1/3rd of his present age. If A was married 24 years ago the...
A boy’s age is 125% of what it was 8 years ago, but 75% of what it will be after 8 years. What is his present age?
In a classroom there are 12 boys and 10 girls. Average age of each boy and each girl is 22 years and 18 years respectively. The sum of ages of all the b...
Present ages of 'A' and 'B' are in the ratio 3:5, respectively. If B's age, 10 years hence from now will be 5 times of A's age, 20 years ago from now, t...
If R’s age is twice the average age of P, Q and R. P’s age is one third the average age of P, Q and R. If Q is 10 years old, the average age...
The ratio of the present ages of P and Q is 8:5 respectively. If the age of P 10 years hence from now will be 100% more than the age of Q 4 years ago fr...
Six years ago, the age ratio of A to B was 5:6. In nine years, their age ratio will become 8:9. Determine the difference between their current ages.
Four years ago, the combined ages of Linda and Joan was 56 years. Four years hence, the ratio of their ages will be 4:5. Find the current age of Linda.
