Question
A cuboid has dimensions 12 cm × 8 cm × 6 cm. If a
cylindrical hole of diameter 4 cm is drilled through the entire length of the cuboid, what is the volume of the remaining solid? (Ï€ = 3.14)Solution
Volume of the cuboid = l × b × h = 12 × 8 × 6 = 576 cm³. Volume of the cylindrical hole = π * r² * h Where diameter = 4 cm, so radius r = 2 cm and height h = 12 cm: Volume of the hole = π * (2²) * 12 = π * 4 * 12 = 48π cm³. Remaining volume = Volume of cuboid - Volume of hole = 576 - 48π. Using π = 3.14 Remaining volume = 576 - 150.72 = 425.28 cm³. Correct option: b) 425.28 cm³
What will come in the place of question mark (?) in the given expression?
? = (40% of 80% of 6400) ÷ 64
360 × 9 ÷ 3 + 120 + 900 ÷ 5 = ?
120% of 25 + 80 X 2 = ?2 - 6
What will come in the place of question mark (?) in the given expression?
48 X 2.5 + 20% of 150 = ? + 166
30% of 750 + ?% of 400 = 25% of 1016 + 3
√1444 + √729 – √2116 = ?
- Simplify:
24% of 150% of 500 + 140 = ? × 8Â
10 × 100 ÷ 5 + 9 = ?
What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?
