Question
In triangle ABC, if angle A = 30°, angle B = 60°, and
side a = 10 cm, find side b.Solution
Using the Law of Sines: a/sinA = b/sinB, hence b = a * (sinB/sinA). b = 10 * (sin60°/sin30°) = 10 * (√3/2)/(1/2) = 10√3 cm. Correct answer : b) 10√3 cm
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