Question
A milkman has a 60-liter mixture of milk and water in
the ratio of 7:5. He sells 'x' liters of the mixture and replaces it with the same amount of a new mixture of milk and water in the ratio of 3:1. As a result, the ratio of milk to water in the final mixture becomes 41:19. Find the value of 'x'.Solution
Answer: A Milk in 60 liters = 60 * 7/12 = 35 liters Water in 60 liters = 60 * 5/12 = 25 liters Milk in x liters = 7x/12 Milk in x liters = 5x/12 After added the milk = 3x/4 Water = x/4 -Constable/1728551292-730.JPG)
(420 + 2x) * 19 = (300 – 2x) * 41 7980 + 38x = 12300 – 82x 120x = 4320 x = 36 liters
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30, 39, 66, ? , 174, 255
- Evaluate: 210 ÷ 15 × 7 + 200 – 50% of 600
