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Answer: A Let the efficiency of Durgesh alone = ‘y’ units/day Then, total work = 21 × y = ‘21y’ units Let the efficiency of Vikash = ‘z’ units/day We have, 8 × z + 7 × y = 21y Or, 8z = 14y So, z:y = 14:8 = 7:4 So, ratio of efficiencies of Vikash and Durgesh is 7:4, respectively So, efficiency of Vikash = (7y/4) = ‘1.75y’ units/day Efficiency of Satish = y × 0.75 = ‘0.75y’ units/day Combined efficiency of Vikash and Satish = 1.75y + 0.75y = ‘2.5y’ units/day According to the question, 2.5y × x + y × 6 = 21y Or, 6y + 2.5xy = 21y Or, 2.5xy = 15y So, x = 15 ÷ 2.5 = 6
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
1587.9 + 9650.98 + 10612.8 =?3 - 2536.67
64.64% of 419.89 + 116.61 = ? x 12.89
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
?% of (136.31 ÷ 16.97 × 75.011) = 179.98
9.992 + (5.01 × 4.98) + ? = 225.03
(9.013 – 15.04) = ? + 7.98% of 5199.98
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?