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    Question

    In an election with two candidates, A and B, 80% of

    registered voters cast ballots. B wins by a margin of 880 votes. If B had received 10% fewer votes, A's vote count would have matched B's. How many registered voters are there?
    A 7500 Correct Answer Incorrect Answer
    B 7700 Correct Answer Incorrect Answer
    C 9900 Correct Answer Incorrect Answer
    D 8900 Correct Answer Incorrect Answer
    E none Correct Answer Incorrect Answer

    Solution

    Let number of votes received by A = a And, the number of votes received by B = b b-a = 800 according to question- b – 10% of b = a + 10% of b 9b/10 = a + b/10 4b/5 = a a/b = 4/5 from b-a = 880 5x-4x = 880 x = 880 number of votes received by A = a = 4x = 3520 And, the number of votes received by B = b = 5x = 4400 Total casted votes = 3520+4400 = 7920 80% of registered voters = 7920 Registered voters = 7920/80 ×100 = 9900

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