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Start learning 50% faster. Sign in nowAnswer: E Quantity I: Let the length of bridge = ‘d’ m So, the length of tunnel = (d + 96) m Also let the speed of bike = ‘x’ m/s So, d/x = 30 d = 30x -----------(1) And, (d + 96)/x= 36 From equation (1): 30x + 96 = 36x x = 16 m/s So, time taken by bike to cover 4.32 km = (4.32 * 1000)/16 = 270 seconds = 4.5 minutes Quantity II: Let time taken by A alone to finish the work = ‘t’ hours So, time taken by B alone to finish the work = ‘2t’ hours (1/t) + (1/2t) = 1/5 3/2t = 1/5 t = 7.5 Time taken by A alone finish the work with its original efficiency = 7.5 hours So, time taken by A alone to finish the work with 5/3 of its original efficiency = 7.5 * (3/5) = 4.5 hours Hence, Quantity I = Quantity II
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I. 81x - 117√x + 40 = 0
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I. 3x2 - 14x + 15 = 0
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I. 15y2 + 4y – 4 = 0
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I. 2p2 + 25p – 13 = 0
II. 2q2 – 19q = 2q + 23
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
I. 8y2- 2y - 21 = 0
II. 2x2+ x - 6 = 0
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
I. x2 - 5x - 14 = 0
II. y2 - 16y + 64 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0