Question
A company has two employees, Employee A and Employee B.
Employee A earns 180,000 annually, and Employee B earns 210,000 annually. If Employee A’s salary is increased by 10% and Employee B’s salary is increased by 7%, what is the new average monthly salary of the two employees?Solution
Monthly earning of Employee A = 180,000 / 12 = 15,000 Monthly earning of Employee B = 210,000 / 12 = 17,500 After a 10% increase, the earning of Employee A = 110% of 15,000 = 16,500 After a 7% increase, the earning of Employee B = 107% of 17,500 = 18,725 New average monthly salary = (16,500 + 18,725) / 2 = 35,225 / 2 = 17,612.5
- 18.22 × 11.99 + 154.15 = ? 
- 386.99 + 397.99 + ? - 232.02 = 35.02 × 31.99 
- 5.55% of 8120 – 66.66% of 540 = ? – 28% of 5500 
- 24.99 × 32.05 + ? - 27.01 × 19.97 = 29.99 × 27.98 
- ? 2 + (39.99 × 10.99 + 7.01) - (39.99 × 2.99 2 + 21.99) = 21.99 × 23.01 
- ? = 22.08 + 13.99 × 22.07 
- Find the approximate value of Question mark(?). No need to find the exact value. - 18.07 × (47.998 ÷ 12.03) + 59.78% of 150.14 – √(255.86) = ... 
- Bijay can complete a task on his own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the... 
- 21% of 6600 + 453.987 =? 
- A salesman is allowed 32% commission on the total sales by him and a bonus of 3% on the sales over Rs. 15000. If the total earnings of a salesman is Rs....