Question
Bijay can complete a task on his
own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the task starting with Bijay, in how many days will the task be completed?Solution
ATQ, Let the total task be 200 units {LCM (25 and 40)} So, efficiency of 'Ajay' = 200 ÷ 25 = 8 units/day And efficiency of 'Bijay' = 200 ÷ 40 = 5 units/day Task done in every 2 days = 8 + 5 = 13 units So, task done in 30 days by 'Ajay' and 'Bijay' = (30/2) × 13 = 195 units Time taken by 'Bijay' to do the remaining work = {(200 - 195)/5} = 1 day So, total time taken = 1 + 30 = 31 days
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
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