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Length of the floor = 11 m 47 cm = 1147 cm Breadth of the floor = 6m 82 cm = 682 cm. Area of the floor = 1147 times; 682 cm^2 The number of square tiles will be least, when the size of each tile is maximum. Therefore, Size of each tile = HCF of 1147 and 682 = 31 Required number of tiles = (1147 x 682)/(31 x 31) = 814
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
240 + 25% of 420 – 145 =? + (2.5 + 8.5) 2
√324 + √484 + 63 = ?2
68% of 450 – 1008 ÷ 14 + 516 ÷ 43 =?
1/6+ 999*53/54 ×9 = ?
125% of 129 ÷ 43 × 28 ÷ 7 = ? ÷ √16
What is (0.08% of 0.008% of 8)1/9 ?
120 × 195 ÷ 13 - ? = 162