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    Question

    I. 6y2 - 17y + 12 = 0 II.

    15x2 - 38x + 24 = 0 In the following questions, two equations numbered I and II are given. You have to solve both questions and give answer among the following options.
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x = y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. 6y2 - 17y + 12 = 0 6y2 - 8y - 9y + 12 = 0 2y (3y - 4) - 3 (3y - 4) = 0 (3y - 4) (2y - 3) = 0 y = 4/3, 3/2 II. 15x2 - 38x + 24 = 0 15x2 - 18x - 20x + 24 = 0 3x (5x - 6) - 4 (5x - 6) = 0 (3x - 4) (5x - 6) = 0 x = 4/3, 6/5 Hence x ≤ y

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