(i) x² – 3x – 40 = 0
(ii) y² + 11y + 30 = 0
(i) x² – 3x – 40 = 0 => x² – 8x + 5x – 40 = 0 => x (x – 8) + 5(x – 8) = 0 => (x – 8) (x + 5) = 0 => x = 8, -5 (ii) y² + 11y + 30 = 0 => y² + 6y + 5y + 30 = 0 => y (y + 6) + 5 (y + 6) =0 => (y + 5) (y + 6) =0 => y = -6, – 5 Hence, x ≥ y.
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