Question
(i) x² – 3x – 40 = 0 (ii) y² + 11y + 30 =
0 In each of these questions, two equations (i) and (ii) are given. You have to solve both the equations and give answers:Solution
(i) x² – 3x – 40 = 0 => x² – 8x + 5x – 40 = 0 => x (x – 8) + 5(x – 8) = 0 => (x – 8) (x + 5) = 0 => x = 8, -5 (ii) y² + 11y + 30 = 0 => y² + 6y + 5y + 30 = 0 => y (y + 6) + 5 (y + 6) =0 => (y + 5) (y + 6) =0 => y = -6, – 5 Hence, x ≥ y.
4999.99 ÷ 10.25 + 379.99 - 160.25 = ?Â
47.78% of 499.98 + (19.89 × 7.76) = √? × 49.84
15.22 × 9.99 + 150.15 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
What approximate value should come in the place of (?) in the following questions?
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1749.8 * √255.77 - ?³ = 19.8 * 1300 + 1488.08What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 14.99 × 25.07
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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