I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I. 27x6 - 152x3 + 125 = 0 Let x³ = a 27a2 - 152a + 125 = 0 27a2 - 125a - 27a + 125 = 0 a(27a - 125) - 1(27a - 125)=0 a=1,125/27 x³=1,125/27 x=1,5/3 II. (216y)6 - 91y3 + 8 = 0 Let y3 = b 216b2- 91b + 8 = 0 216b2- 27b - 64b + 8 = 0 27b(8b - 1) - 8(8b - 1) = 0 b = 1/8,8/27 y3 = 1/8,8/27 y = 1/2,2/3 Hence, x > y
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In the following question below are given some statements followed by some conclusions based on those statements. Taking the given statements to be tru...
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Statements:
