Question
(I) `p^2 + p = 56` (II) `q^2 - 17q
+ 72 = 0` In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if; (1) p>q, (2) p<q, (3) p=q, (4) p ≥ q (5) p ≤ qSolution
I. `p^2 + p = 56` or `p^2 + p - 56 = 0` `p^2 + 8p - 7p - 56 = 0` or , (p – 7)(p + 8) = 0 Or p = - 8 or 7 , II. `q^2 - 17q + 72 = 0` , or (q – 8)(q – 9) = 0, or q = 8 or 9, Hence , q > p
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