Question
I. 3y² - 7 y + 2= 0 II. 24x² + 26 x
– 5= 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 3y² - 7 y + 2= 0 3y² - y - 6 y + 2= 0 y (3 y – 1) – 2(3 y – 1) = 0 (y – 2) (3 y – 1) = 0 ∴ y = 2, 1/3 II. 24x² + 26 x – 5= 0 24x² - 4 x + 30 x – 5= 0 4 x(6 x – 1) + 5 (6 x – 1) = 0 (4 x + 5) (6 x – 1) = 0 ∴ x = 1/6, -5/4 Hence, x<y
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