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    Question

    I. 2x2– 25x + 33 = 0 II.

    3y2+ 40y + 48 = 0
    A If x > y Correct Answer Incorrect Answer
    B If x ≥ y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 2x2 – 25x + 33 = 0 2x2 – 3 x – 22x + 33 = 0 x (2 x – 3) – 11(2 x – 3) = 0 (x – 11) (2 x – 3) = 0 x = 11, 3/2 II. 3y2 + 40y + 48 = 0 3y2 + 36y + 4 y + 48 = 0 3 y(y + 12) + 4(y + 12) = 0 (y + 12) (3 y + 4) = 0 y = – 12, -4/3 Hence, x > y

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