Question
I. 27x6-152x3+125=0 II.
216y6Â -91y3+8=0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answerÂSolution
I. 27x6-152x3+125=0 Let x³ = a 27a2-152a+125=0 27a2-125a-27a+125=0 a(27a-125)-1(27a-125)=0 a=1,125/27 x³=1,125/27 x=1,5/3 II. 216y6- 91y3 + 8=0 Let y3=b 216b2-91b+8=0 216b2-27b-64b+8=0 27b(8b-1)-8(8b-1)= 0 b=1/8,8/27 y3= 1/8,8/27 y=1/2,2/3 Hence, x>y
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