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    Question

    I. 27x6-152x3+125=0 II.

    216y6 -91y3+8=0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer 
    A If x ≥y Correct Answer Incorrect Answer
    B If x ≤y Correct Answer Incorrect Answer
    C If x>y Correct Answer Incorrect Answer
    D If x Correct Answer Incorrect Answer
    E If x=y or relationship between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 27x6-152x3+125=0 Let x³ = a 27a2-152a+125=0  27a2-125a-27a+125=0  a(27a-125)-1(27a-125)=0  a=1,125/27  x³=1,125/27  x=1,5/3  II. 216y6- 91y3 + 8=0 Let y3=b 216b2-91b+8=0  216b2-27b-64b+8=0  27b(8b-1)-8(8b-1)= 0  b=1/8,8/27  y3=  1/8,8/27 y=1/2,2/3  Hence, x>y

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