Question

    I. 56x² - 99x + 40 = 0

    II. 8y² - 30y + 25 = 0

    A if x>y Correct Answer Incorrect Answer
    B if x≥y Correct Answer Incorrect Answer
    C if x Correct Answer Incorrect Answer
    D if x ≤y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 56x² - 99x + 40 = 0 56x² - 35x – 64x + 40 = 0 7x(8x – 5) – 8(8x – 5) = 0 (7x – 8) (8x – 5) = 0 x = 8/7, 5/8 II. 8y² - 30y + 25= 0 8y² - 10y - 20y + 25= 0 2y(4y – 5) – 5(4y - 5) = 0 (2y – 5) (4y – 5) = 0 y = 5/2, 5/4 Hence x < y

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