The cost price of a laptop is Rs. (k + 400), and the cost price of a tablet is Rs. (k − 600). The laptop is sold at a 25% loss, and the tablet is sold at a 30% profit. If the selling price of the tablet is Rs. 1670 more than the selling price of the laptop, find the value of k + 200.

ATQ, Cost price of laptop = Rs. (k + 400) Cost price of tablet = Rs. (k − 600) The laptop is sold at 25% loss. So, selling price of laptop = 75% of (k + 400) Selling price of laptop = 75(k + 400)/100 The tablet is sold at 30% profit. So, selling price of tablet = 130% of (k − 600) Selling price of tablet = 130(k − 600)/100 Given: Selling price of tablet − Selling price of laptop = Rs. 1670 130(k − 600)/100 − 75(k + 400)/100 = 1670 [130(k − 600) − 75(k + 400)]/100 = 1670 130k − 78000 − 75k − 30000 = 1670 × 100 55k − 108000 = 167000 55k = 167000 + 108000 55k = 275000 k = 275000/55 k = 5000 Required value = k + 200 Required value = 5000 + 200 = 5200